Posted by LadyJustice85 on Wednesday, June 1, 2011 at 11:33am.
a)k=1-(0.07+0.20+0.38+0.13)=0.22
b)M(X)=0*0.07+1*0.20+2*0.38+3*0.22+4*0.13=
=2.14
c)M(X^2)=0*0.07+1*0.20+4*0.38+9*0.22+
+16*0.13=5.78
The standard deviation=
=sqrt(M(X^2)-M(X)^2)=1.10
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