Posted by **Paul** on Tuesday, May 31, 2011 at 11:48pm.

A chemistry teacher needs 2.5 liters of a sulfuric acid solution that is 20% sulfuric acid and 80% water . He has 2 liters of a 15% sulfuric acid solutionleft over from earlier laboratory exercises. He also has 44 liters of a 50% solution. Let x represent the number of liters of the 15% solution that can be mixed with Y liters of the 50% solution to make 2.5 liters of the needed 20% solution. Which of the following shows a system of equations that could get the solved to find the amounts of the 15% and 50% solutions that could be mixed to get the required solution?

A) X+Y=2.5

0.15X+0.50Y=0.20

B) x+y=0.20(2.5)

0.15x+0.50y=2.5

C) x+y=2.5

0.15x+0.50y=0.20(2.5)

D)x+y=0.65

x+y=0.20(2.5)

## Answer This Question

## Related Questions

- Chemistry - A chemist needs a 50% of sulfuric acid. She mix 2 liters of 20% of ...
- Algebra - A chemist has two solutions of sulfuric acid. The first is one half ...
- algebra - mark needs to make 15% sulfuric acid for a lab. how much sulfuric acid...
- Chemistry - Automobile batteries contain sulfuric acid, which is commonly ...
- chemistry - calculate what volume of sulfuric acid solution(specific gravity=1....
- Math - A solution of 10% sulfuric acid and one of 25% sulfuric acid are to be ...
- chemistry - Methanol + Butanoic acid + Sulfuric acid = Pinapple Methanol + ...
- AP Chemistry - Sulfuric acid (H2SO4) is a very strong diprotic acid. If 0.036 ...
- chemistry - A solution is 40% acetic acid by mass. The density of this solution ...
- Chemistry - Sulfuric acid (H2SO4) is a very diprotic acid. If 0.046 moles of ...

More Related Questions