Posted by Adam on Tuesday, May 31, 2011 at 11:18pm.
heat lost by 120 C Cu + heat gained by 40 C Cu = 0
I would choose some convenient number like 10 g for one of the pieces and 20 g for the other; substitute into the
[mass x specific heat x (Tfinal-Tinitial)] + [mass x specific heat x (Tfinal-Tinitial)] = 0
Solve for Tfinal.
I obtained an answer approximately 90 C.
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