Posted by jj on Tuesday, May 31, 2011 at 10:53pm.
*** I meant Kp = 4.0 x 10^18
If Kp = 4.0E18 = (HCl)^2/(H2)(Cl2)
Isn't this just a matter of substituting values for (H2) and (Cl2) and solving for (HCl)? Or is it more complicated than that.
yes i did that but the answer i get is weird
True you obtained a huge number for (HCl); however, with a K as large as 10^18 you know (HCl) must be very very large.
Is 8.35 x 10^9mPa the right answer?
I don't know
@DrBob222: is that the answer?
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