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March 30, 2017

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verifying a solution.

4cos^2 2x-2=0

  • trig - ,

    4cos^2 2x-2=0
    cos^2 (2x) = 1/2
    cos (2x) = ± 1/√2
    2x = 45° or 2x = 135° or 2x = 225° or 2x = 315°

    x = 22.5°, 67.5°, 112.5°, 157.5, ...

    the period of cos 2x is 180°, so adding 180° to any of the above answers will produce a new answer.
    So there is an infinite number of solutions.

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