Balance the equation in aqueous basic solution:

NO2-(aq) + Al(s) → NH3(aq) + AlO2-(aq)

I know how to balance equations in acidic solutions, but I get lost doing the basic one, please help?

NO2-(aq) + 2Al(s) + H2O + OH→ NH3(aq) + 2AlO2-(aq)

This is what I got

That is 100% correct.

I don't balance them this way but ONE way is to balance in acidic soln (since you can do that already, then add OH^- to each H^+ (and to keep the equation balanced you add OH^- to the other side).

Sure, I'd be happy to help you balance the equation in aqueous basic solution!

Let's start by writing down the unbalanced equation:

NO2-(aq) + Al(s) → NH3(aq) + AlO2-(aq)

The first step is to balance the atoms other than hydrogen and oxygen. In this case, we have one nitrogen (N) atom on the left and one on the right, and one aluminum (Al) atom on the left and one on the right. So, we don't need to do anything to balance these.

Next, let's balance the oxygen atoms. On the left, we have two oxygen (O) atoms from the NO2- ion, and on the right, we have three oxygen atoms - one from NH3, and two from AlO2-. To balance the oxygens, we need to add one more oxygen to the NH3 product. We can do this by adding H2O.

The equation now looks like this:

NO2-(aq) + Al(s) → NH3(aq) + AlO2-(aq) + H2O

Now, let's balance the hydrogen atoms. On the left, we have no hydrogen atoms, and on the right, we have three from NH3 and one from H2O. To balance the hydrogens, we can add OH- to the other side of the equation.

The equation now looks like this:

NO2-(aq) + Al(s) + OH-(aq) → NH3(aq) + AlO2-(aq) + H2O

Finally, let's balance the charges. On the left, we have a -1 charge from the NO2-, and on the right, we have a -1 charge from AlO2-. To balance the charges, we can add an electron (e-) to the left side of the equation.

The final balanced equation in aqueous basic solution is:

NO2-(aq) + Al(s) + OH-(aq) + e- → NH3(aq) + AlO2-(aq) + H2O

And voila, the equation is balanced in aqueous basic solution! I hope this helps, and if you have any more questions, feel free to ask!

To balance the given equation in aqueous basic solution, you will need to follow these steps:

Step 1: Balance the atoms that are not oxygen or hydrogen.

In this case, we only have nitrogen and aluminum atoms to balance. The number of nitrogen atoms on the left side is 1, while the right side has 1 nitrogen atom in NH3. Therefore, the nitrogen atoms are already balanced. The number of aluminum atoms on the left side is 1, so we need 1 aluminum atom on the right side as well. The equation remains as:

NO2-(aq) + Al(s) → NH3(aq) + AlO2-(aq)

Step 2: Balance the oxygen atoms by adding water (H2O) molecules.

Count the number of oxygen atoms on the left and right side of the equation. On the left side, we have 2 oxygen atoms from NO2-. On the right side, we have 2 oxygen atoms from AlO2-. This means the oxygen atoms are already balanced.

Step 3: Balance the hydrogen atoms.

Count the number of hydrogen atoms on the left and right side of the equation. On the left side, we have 0 hydrogen atoms. On the right side, we have 3 hydrogen atoms from NH3. To balance the hydrogen atoms, we need to add OH- ions to the left side of the equation. Each OH- ion contains both an oxygen and a hydrogen atom. So we add 3 OH- ions to the left side:

NO2-(aq) + Al(s) + 3OH-(aq) → NH3(aq) + AlO2-(aq)

Step 4: Balance the charges.

Check the overall charge on both sides of the equation. On the left side, NO2- has a charge of -1, and OH- has a charge of -1 each. On the right side, NH3 has no charge, and AlO2- has a charge of -2. To balance the charges, we need to add 2 electrons (e-) to the left side:

NO2-(aq) + Al(s) + 3OH-(aq) + 2e- → NH3(aq) + AlO2-(aq)

Step 5: Balance the electrons.

Now, we need to balance the number of electrons on both sides of the equation. On the left side, we have 2 electrons, while on the right side, we have none. To balance the electrons, we need to add 2 electrons to the right side of the equation:

NO2-(aq) + Al(s) + 3OH-(aq) + 2e- → NH3(aq) + AlO2-(aq) + 2e-

Step 6: Simplify the equation.

Finally, simplify the equation by canceling out the electrons:

NO2-(aq) + Al(s) + 3OH-(aq) → NH3(aq) + AlO2-(aq) + 2e-

Therefore, the balanced equation in aqueous basic solution is:

NO2-(aq) + Al(s) + 3OH-(aq) → NH3(aq) + AlO2-(aq) + 2e-