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algebra

posted by on .

x=3-3y x+3y=-6


need to find the graph points

  • algebra - ,

    First line:

    x=3-3y

    3y=3-x Divide with 3

    y=1-x/3

    y= -x/3 + 1

    y=(-1/3)*x +1

    Second line:

    x+3y= -6

    3y= -6-x Divide with 3

    y= -2 -x/3

    y= -x/3 - 2

    y= (-1/3)*x -2


    The equation of a straight line is usually written this way:

    y = mx + b

    m = Slope or Gradient (how steep the line is)

    b = the Y Intercept (where the line crosses the Y axis)

    In this case slope= -1/3 for both lines,so lines are parallel.

    First line has y-Intercept 1

    Second line has y-Intercept -2

    Now in google type:
    functions graphs online

    When you see list of results clic on:
    rechneronline.de/function-graphs/

    When page be open in blue rectangle type:
    -x/3 + 1

    in gray rectangle type:
    -x/3 - 2

    and click option Draw

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