Wednesday

March 4, 2015

March 4, 2015

Posted by **Rebecca** on Tuesday, May 31, 2011 at 11:37am.

a) x^2 - 7x + 12 = 0

a = 1 b = -7

x = -b +/- the sr of b^2 - 4ac /2a

7 +/- the sr of -7^2 - 4(1)(12) /2a

7 +/- the sr of -49 - 48 /2a

7 +/- the sr of -97 /2a

7 +/- 97 /2a

-90/2=-45

-104/2= 54

The roots are -45 and 54.

did i solve this correctly?

- gr 10 math -
**PsyDAG**, Wednesday, June 1, 2011 at 2:52amx^2 - 7x + 12 = 0

The 12 can factor into -3 and -4 to add to -7 in the middle term.

(x-3)(x-4) = 0

x = 3 or 4.

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