Posted by **Rebecca** on Tuesday, May 31, 2011 at 11:23am.

The playing surface in the game of curling is a rectangular sheet of ice with an area of about 225 m^2. The width is about 40m less than the length. Find the approximate dimensions of the playing surface.

How would i solve this?

- gr10 math -
**Henry**, Wednesday, June 1, 2011 at 4:02pm
Length = L meters.

Width = (L-40) Meters.

L * (L-40) = 225m^2,

L^2 - 40L = 225,

L^2 - 40L - 225 = 0,

(L-5)(L+45) = 0,

- gr10 math -
**Henry**, Wednesday, June 1, 2011 at 4:11pm
Length = L meters.

Width = (L-40) Meters.

L * (L-40) = 225m^2,

L^2 - 40L = 225,

L^2 - 40L - 225 = 0,

(L+5)(L-45) = 0,

L+5 = 0,

L = -5.

L-45 = 0,

L=45.

Choose positive value of L:

L = 45m = Length.

Width = L-40 = 45-40 = 5m.

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