Math
posted by Eric on .
A square and four congruent rectangles are arranged in a larger square. The smaller square and each of the rectangles have the same perimeter.Determine the ratio of the length of a side of the larger square to the length of side of the smaller square.

Let A is the length of a side of the larger square, a  of the smaller square.
The length of the smaller side of
a rectangle is (Aa)/2, the length of
the bigger side is (Aa)/2+a.
4a=2((Aa)/2+(Aa)/2+a)
4a=2A
A/a=2/1