Saturday

October 25, 2014

October 25, 2014

Posted by **Armando** on Monday, May 30, 2011 at 12:28am.

f(x) = x^3 + 2x^2 - 6x + 8

- find real and complex 0 -
**Reiny**, Monday, May 30, 2011 at 8:51amf(±1) ≠ 0

f(±2) ≠ 0

but f(-4) = 0

so x+4 is a factor

I then used synthetic division to get

(x+4)(x^2 - 2x + 2) = 0

the real root is x = -4

Use the quadratic formula to get the two complex roots of

1+i and 1-i

- find real and complex 0 -
**Mgraph**, Monday, May 30, 2011 at 9:03amf(x)=x^3+4x^2-2x^2-8x+2x+8=(x^3+4x^2)-

(2x^2+8x)+(2x+8)=x^2(x+4)-2x(x+4)+2(x+4)=

(x+4)(x^2-2x+2)

x+4=0 => x=-4

or

x^2-2x+2=0 => x=1+i or x=1-i

**Answer this Question**

**Related Questions**

college algebra - 1. solve the following logarithmic equation log_8(x+8)+log_8(x...

Math - Find all complex zeros for the following polynomial function. Please show...

Find the Bounds on the real zeros - Find the bounds on the real zeros of the ...

calculus - use rational zeros theorem to find all the real zeros of the ...

Math #2 - Can you show me the work to get these answers also? 1.Given g(x)=x^3+...

college algebra - use the rational zeros theorem to find all the real zeros of ...

algebra - find all complex zeros for the following polynomial function please ...

college algebra - Find the real and complex zeros of the following function. f(x...

college algebra - Find the real and complex zeros of the following function. f(x...

Precalculus - Find the bounds on the real zeros of the following function. ...