Posted by Aria on Sunday, May 29, 2011 at 10:01pm.
Find an equation of the line containing pair of points
(1/6, 1/3) and (5/6, 3)
I can't seem to figure out the slope right, which apparently is 5. How does one get a five slope out of all these fractions?!!!
To find the slope 31/3 = 8/3 over
5/6  1/6 = 4/6 = 2/3
What am I doing wrong?

Algebra  Reiny, Sunday, May 29, 2011 at 10:06pm
so the numerator is 8/3 and the denominator is 2/3
then (8/3) / (2/3)
= (8/3)(3/2) = 4 , not 5
equation: y = 4x + b
plug in (1/6, 1/3)
1/3 = 2/3 + b
b = 1/3
y = 4x  1/3

Algebra  Aria, Sunday, May 29, 2011 at 10:23pm
Hi,
I got four also, but the program I ran gave me the answer as 5x +7/6. What bothers me about the program is we have to take tests with the program and the problems don't work out to be what our workbook says.
Thanks for your feedback.
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