Monday

January 26, 2015

January 26, 2015

Posted by **Ashley** on Saturday, May 28, 2011 at 11:35pm.

- Math -- assistance needed -
**Writeacher**, Sunday, May 29, 2011 at 8:02amPlease type your

__subject__in the**School Subject**box. Any other words,__including obscure abbreviations__, are likely to delay responses from a teacher who knows that subject well.

- Juwayria Highscholl -
**MathMate**, Sunday, May 29, 2011 at 10:31amFor your security, please refrain from posting the name of your school.

Let O represent the observer,

B = base of the building (vertically below the observer O), and

S = the observed ship.

OBS represents a right-triangle right-angled at B.

Angle of depression

=∠BSO

= 10°

Solve the right triangle:

OB = 30m

&BSO = 10°

tan(10°)=OB/BS = 30m / BS

Solve for BS

BS = 30m /tan(10°)

=30m / 0.17633 (approx.)

= 170 m (approx.)

**Answer this Question**

**Related Questions**

Maths - An observer at the top of a lighthouse 55m Hugh sights a ship at a sea ...

Math(angle of depression) i need help please.. - An observer on top of a cliff ...

physical geography - If a ship's flag is 36' above sea level, could it be seen ...

HELP!!!! - Lee is on a cliff 360 m above sea level, the angle of depression of a...

maths - From an aircraft flying at 8000 metres above sea level the angle of ...

geometry - Two buildings are separated by an alley. Joe is looking out of a ...

calculus - A lifeguard was staring at a ship in the distance, and watched the ...

11th grade - A lifeguard was staring at a ship in the distance, and watched the ...

check set up trigonometry - Lee is on a cliff 360 m above sea level, the angle ...

maths - A tourist viewing Sydney Harbour from a building 180 metres above sea ...