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July 31, 2014

July 31, 2014

Posted by **Ashley** on Saturday, May 28, 2011 at 11:35pm.

- Math -- assistance needed -
**Writeacher**, Sunday, May 29, 2011 at 8:02amPlease type your

__subject__in the**School Subject**box. Any other words,__including obscure abbreviations__, are likely to delay responses from a teacher who knows that subject well.

- Juwayria Highscholl -
**MathMate**, Sunday, May 29, 2011 at 10:31amFor your security, please refrain from posting the name of your school.

Let O represent the observer,

B = base of the building (vertically below the observer O), and

S = the observed ship.

OBS represents a right-triangle right-angled at B.

Angle of depression

=∠BSO

= 10°

Solve the right triangle:

OB = 30m

&BSO = 10°

tan(10°)=OB/BS = 30m / BS

Solve for BS

BS = 30m /tan(10°)

=30m / 0.17633 (approx.)

= 170 m (approx.)

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