Posted by Ashley on Saturday, May 28, 2011 at 11:35pm.
An obsever is looking out to sea from the top of a building that is 30 m above sea leavel. He observera ship at an angle of depression of 10. How far is the ship from the foot of the bulding?

Math  assistance needed  Writeacher, Sunday, May 29, 2011 at 8:02am
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Juwayria Highscholl  MathMate, Sunday, May 29, 2011 at 10:31am
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Let O represent the observer,
B = base of the building (vertically below the observer O), and
S = the observed ship.
OBS represents a righttriangle rightangled at B.
Angle of depression
=∠BSO
= 10°
Solve the right triangle:
OB = 30m
&BSO = 10°
tan(10°)=OB/BS = 30m / BS
Solve for BS
BS = 30m /tan(10°)
=30m / 0.17633 (approx.)
= 170 m (approx.)
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