Posted by **Ashley** on Saturday, May 28, 2011 at 11:35pm.

An obsever is looking out to sea from the top of a building that is 30 m above sea leavel. He observera ship at an angle of depression of 10. How far is the ship from the foot of the bulding?

- Math -- assistance needed -
**Writeacher**, Sunday, May 29, 2011 at 8:02am
Please type your __subject__ in the **School Subject** box. Any other words, __including obscure abbreviations__, are likely to delay responses from a teacher who knows that subject well.

- Juwayria Highscholl -
**MathMate**, Sunday, May 29, 2011 at 10:31am
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Let O represent the observer,

B = base of the building (vertically below the observer O), and

S = the observed ship.

OBS represents a right-triangle right-angled at B.

Angle of depression

=∠BSO

= 10°

Solve the right triangle:

OB = 30m

&BSO = 10°

tan(10°)=OB/BS = 30m / BS

Solve for BS

BS = 30m /tan(10°)

=30m / 0.17633 (approx.)

= 170 m (approx.)

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