Thursday
March 23, 2017

Post a New Question

Posted by on Saturday, May 28, 2011 at 5:54pm.

f(x)=2x^3-x^2+1 [1,4]=interval

Set up the limit process (once with right endpts, and the other with left entdpts.) to find the area under the curve and above the x-axis on the given interval

Should the right and left endpt limit set ups have the same area? If so what is it?

PLEASE HELP.....I GOT 107.55 BUT IT IS NOT THE RIGHT ANSWER AND I DON'T SEE HOW THERE CAN BE A DIFFERENCE IN SETTING UP

  • calculus!!! please help!!! - , Saturday, May 28, 2011 at 11:41pm

    f(x) is always above the x axis in that interval. Therefore just integrate the function from 1 to 4. I don't know what you mean by "the limit process".

    The indefinite integral is x^4/2 -x^3/3 +x. That equals 128 -21.33 +4 = 110.67 at x = 4 and 0.50 -0.33 +1 = 1.17 at x = 1.

    The area should be 110.67-1.17 = 109.50

    My algebra tends to be sloppy, so my answer could be wrong, too.

  • calculus!!! please help!!! - , Sunday, May 29, 2011 at 5:08pm

    thanks so much!!!

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question