Posted by lisa on Saturday, May 28, 2011 at 5:46pm.
I am not sure how much your book gives you.
I will assume that you know that:
E = [ 1/(2pieo) ] lambda/r
where lambda = charge per unit length
and
r is distance perpendicular to the line
then
Voltage potential of point a at ra with respect to potential at point b at rb is:
Va -Vb = integral from a to b of E dr
= [lambda/(2pieo)]integral dr/r
= [lambda/(2pieo)] ln (rb/ra)
calculate that
now
work done = charge* voltage difference
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