Posted by **Theo** on Friday, May 27, 2011 at 11:38pm.

The product of three consecutive odd integers reduced by 23 is 99 less than the cube of the sum of the smallest number and 2. Compute the mean of the three integers.

- Math -
**Reiny**, Friday, May 27, 2011 at 11:45pm
let the 3 consecutive numbers be

x-2, x and x+2

(x-2)(x)(x+2) - 23 = (x-2 + 2)^3 - 99

x(x^2 - 4) - 23 = x^3 - 99

x^3 - 4x = x^3 - 99 + 23

-4x = -76

x = 19

the three numbers are 17, 19, and 21

and their mean is 19

## Answer this Question

## Related Questions

- math - A. Four times one odd integer is 14 less than three times the next even ...
- algebra - Five times the smallest of three consecutive odd integers is ten more ...
- smallest of 3 integers - The sum of the reciprocals of three consecutive ...
- math - the sum of the reciprocals of three consecutive positive integers is ...
- Algebra - The sum of the squares of the largest and smallest of three ...
- math - 1. The largest of five consecutive integers is twice the smallest. Find ...
- Math Algebra - Two times the smallest of three consecutive odd integers is one ...
- Math - 1. if the largest of three consecutive even integers is multiplied by 5, ...
- math - Consecutive integers are integers that follow each other in order (for ...
- math - there are three consecutive positive integers such that the sum of the ...

More Related Questions