Posted by Theo on Friday, May 27, 2011 at 11:38pm.
The product of three consecutive odd integers reduced by 23 is 99 less than the cube of the sum of the smallest number and 2. Compute the mean of the three integers.

Math  Reiny, Friday, May 27, 2011 at 11:45pm
let the 3 consecutive numbers be
x2, x and x+2
(x2)(x)(x+2)  23 = (x2 + 2)^3  99
x(x^2  4)  23 = x^3  99
x^3  4x = x^3  99 + 23
4x = 76
x = 19
the three numbers are 17, 19, and 21
and their mean is 19
Answer This Question
Related Questions
 math  A. Four times one odd integer is 14 less than three times the next even ...
 algebra  Five times the smallest of three consecutive odd integers is ten more ...
 smallest of 3 integers  The sum of the reciprocals of three consecutive ...
 math  the sum of the reciprocals of three consecutive positive integers is ...
 Algebra 2  Find three consecutive odd positive integers such that 3 times the ...
 math  What is the smallest of three consecutive integers if the sum of the ...
 math  What is the smallest of three consecutive integers if the sum of the ...
 Algebra  The sum of the squares of the largest and smallest of three ...
 math  What is the smallest of three consecutive integers if the sum of the ...
 math  1. The largest of five consecutive integers is twice the smallest. Find ...
More Related Questions