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April 20, 2014

April 20, 2014

Posted by **john** on Friday, May 27, 2011 at 10:14pm.

- trig -
**drwls**, Friday, May 27, 2011 at 10:28pmsec(90 -theta) = 1/cos(90 - theta)

= 1/(cos90 cos theta + sin 90 sin theta)

= 1/sin theta

= csc theta

You could get the same result by considering a right triangle. The sec of one acute angle is the csc of the other.

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