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July 24, 2014

July 24, 2014

Posted by **Alexis** on Friday, May 27, 2011 at 5:48pm.

- Algebra 2 -
**Reiny**, Friday, May 27, 2011 at 7:34pmthis is a GS where

a = 1/3

r =1/3

sum(infinite # of terms) = a/(1-r)

= (1/3)/(1 - 1/3)

= (1/3) / (2/3)

= (1/3)(3/2)

= 1/2

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