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October 20, 2014

October 20, 2014

Posted by **shinel** on Friday, May 27, 2011 at 3:37pm.

2 cot squared x + 3 csc x=0

- trig -
**Reiny**, Friday, May 27, 2011 at 7:42pmWe know that

1 + cot^2 Ø = csc^2 Ø

so our equation is

2(csc^ x - 1) + 3csc x = 0

2 csc^2 x + 3csc x - 2 = 0

(2cscx -1)(cscx + 2) = 0

cscx = 1/2 or cscx = -2

or

sinx = 2 (not possible) or sinx = -1/2

so x must be in III or IV

x = 7π/6 or 11π/6

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