Friday

August 1, 2014

August 1, 2014

Posted by **David** on Friday, May 27, 2011 at 1:02pm.

- algebra 2 -
**MathMate**, Friday, May 27, 2011 at 7:19pmThis means that

A/P=2, or

e^(rt)=2

log(e^(rt))=log_{e}2

rt=log_{e}2

t=(log_{e}2)/r

=(log_{e}2)/0.062 years

=?

- algebra 2 -
**MathMate**, Friday, May 27, 2011 at 7:23pmThis means that

A/P=2, or

e^(rt)=2

log(e^(rt))=log_{e}2

rt=log_{e}2

t=(log_{e}2)/r

=(log_{e}2)/0.062 years

=?

Note:

This is actually the rule of 69.31, as follows:

The number of years to double money multiplied by the interest rate of p% compounded*continuously*is 69.31.

- algebra 2 -
**kim**, Friday, October 28, 2011 at 4:16pmEli deposited $1400 at 6.5% interest compounded quarterly. How much money will he have at the end of 8 years?

- algebra 2 -
**Anonymous**, Tuesday, April 8, 2014 at 1:18pmAn initial amount of money is placed in an account at an interest rate of per year, compounded continuously. After three years, there is in the account. Find the initial amount placed in the account. Round your answer to the nearest cent.

- algebra 2 -
**lizzy**, Monday, April 14, 2014 at 12:00am0.3=10^06x

**Related Questions**

algebra - The amount of money in an account with continuously compounded ...

math - The amount of money in an account with continuously compounded interest ...

algebra 2 - What will be the amount in an account with initial principal $6000 ...

algebra II - What will be the amount in an account with initial principal $6000 ...

Alg 2 - Suppose you deposit a principal amount of p dollars in a bank account ...

Alg2 - Help....Help... Suppose you deposit a principal amount of p dollars in a ...

math - Suppose that you have $12,500 to invest over a 4 year period. There are ...

Algebra - Show how you substitute the values into the formula, then use your ...

Algebra - Use the compound interest formula $18,000 is invested in an account ...

algebra - A continuously compounded account starts with $1500 in principal. The...