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November 27, 2014

November 27, 2014

Posted by **David** on Friday, May 27, 2011 at 1:02pm.

- algebra 2 -
**MathMate**, Friday, May 27, 2011 at 7:19pmThis means that

A/P=2, or

e^(rt)=2

log(e^(rt))=log_{e}2

rt=log_{e}2

t=(log_{e}2)/r

=(log_{e}2)/0.062 years

=?

- algebra 2 -
**MathMate**, Friday, May 27, 2011 at 7:23pmThis means that

A/P=2, or

e^(rt)=2

log(e^(rt))=log_{e}2

rt=log_{e}2

t=(log_{e}2)/r

=(log_{e}2)/0.062 years

=?

Note:

This is actually the rule of 69.31, as follows:

The number of years to double money multiplied by the interest rate of p% compounded*continuously*is 69.31.

- algebra 2 -
**kim**, Friday, October 28, 2011 at 4:16pmEli deposited $1400 at 6.5% interest compounded quarterly. How much money will he have at the end of 8 years?

- algebra 2 -
**Anonymous**, Tuesday, April 8, 2014 at 1:18pmAn initial amount of money is placed in an account at an interest rate of per year, compounded continuously. After three years, there is in the account. Find the initial amount placed in the account. Round your answer to the nearest cent.

- algebra 2 -
**lizzy**, Monday, April 14, 2014 at 12:00am0.3=10^06x

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