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Posted by on Friday, May 27, 2011 at 7:38am.

what is the maximum velocity of a 6 kg object oscillation on a 4 m string. If the mass starts when the string makes a 45 degree angle with horizontal when the object is released from rest

  • physics - , Friday, May 27, 2011 at 7:49am

    Use energy conservation.

    Potential energy change = maximum kinetic energy

    M g L (1 - cos 45) = (1/2) M Vmax^2

    Mass M cancels out. L is the string length

    Vmax^2 = g*L*(0.5858)
    Vmax = 0.7654 sqrt(g L)

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