Posted by john on Friday, May 27, 2011 at 12:21am.
CH4 + 2O2 ==> CO2 + 2H2O
So 1L CH4 requires 2 L pure O2.
Since air is only 20% O2 (that's 1/5), then 1L CH4 requires 5*2 = 10L air.
Try it in reverse. 10L air x 0.2 = 2 moles pure O2.
mole ratio air/methane = 10/1
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