Post a New Question

trig

posted by .

A plane is flying 225 mph heading South 25°West. The wind is blowing South 80°East at 60 mph.

What is the bearing of the plane?
What is the smallest angle of the triangle?
What is the largest angle of the triangle?
What is the remaining angle of the triangle?
What is the ground speed of the plane?

  • trig -

    Vp=225mi/h@(270-25) + 60mi/h@(270+80).
    Vp = 225mi/h@245deg + 60mi/h@350deg.
    Vp=(225cos245+60cos350) +
    i(225sin245+60sin350).

    Vp = (-95.1+59.1) + i(-203.9-10.4),
    Vp = -36 - i214.3,

    1. tan(Ar) = -214.3 / -36 = 5.95,
    Ar = 80.5deg.
    A = Ar + 180 = 80.5 + 180 = 260.5deg. =
    Direction(bearing).

    2. 90 - Ar = 90 - 80.5 = 9.5deg. = smallest angle.

    3. 90deg = Largest angle.

    4. 90 - 9.5 = 80.5deg.

    5. Vp^2 = (-36)^2 + (214.3)^2 = 47,220.49,
    Vp = 217.3mi/h.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question