Posted by Anonymous on Thursday, May 26, 2011 at 10:28am.
Vp=225mi/h@(270-25) + 60mi/h@(270+80).
Vp = 225mi/h@245deg + 60mi/h@350deg.
Vp=(225cos245+60cos350) +
i(225sin245+60sin350).
Vp = (-95.1+59.1) + i(-203.9-10.4),
Vp = -36 - i214.3,
1. tan(Ar) = -214.3 / -36 = 5.95,
Ar = 80.5deg.
A = Ar + 180 = 80.5 + 180 = 260.5deg. =
Direction(bearing).
2. 90 - Ar = 90 - 80.5 = 9.5deg. = smallest angle.
3. 90deg = Largest angle.
4. 90 - 9.5 = 80.5deg.
5. Vp^2 = (-36)^2 + (214.3)^2 = 47,220.49,
Vp = 217.3mi/h.
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