Posted by Amy~ on Wednesday, May 25, 2011 at 11:14pm.
Assume that the observer is at sea-level.
The horizontal line is tangent to the earth at Oahu,
distance = 40 miles = 40*5280'=211200'
The radius of the earth is
r=3960 miles=20908800'
and is perpendicular to the horizontal line above.
Hypotenuse
=sqrt(211200²+20908800²)
=2745600√(58)'
Visible height
= hypotenuse - radius of earth
= 1066.64' < 4961
Therefore the said peak is visible.
So the question is basically asking which mountains peaks can be seen from Oahu.
Island Distance(Mi) Mountain Height(ft)
Lanai - 65 - Lanaihale - 3,370
Maui - 110 - Haleakala - 10,023
Hawaii - 190 - Mauna Kea - 13,796
Molokai - 40 - Kamakou - 4,961
A) Radius of earth= 3960 mi.
Determine angle formed at the center of the earth.
B) Determine length of the hypotenuse.
Is Lanai-hale visible from Oahu?
C) Repeat parts A & B for the other 3 islands
D) Which 3 Mountains are visible from Oahu?
Can someone draw me a diagram and explain to me what to do step by step? please and thank you!!
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