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October 20, 2014

October 20, 2014

Posted by **Amy~** on Wednesday, May 25, 2011 at 11:14pm.

Island Distance(Mi) Mountain Height(ft)

Molokai - 40 - Kamakou - 4,961

A) Radius of earth= 3960 mi.

Determine angle formed at the center of the earth.

B) Determine length of the hypotenuse.

Could someone go through the steps to solve this?

I have already done so but I seem to get close but different answers I need to check my work.

- Math -
**MathMate**, Thursday, May 26, 2011 at 9:55amAssume that the observer is at sea-level.

The horizontal line is tangent to the earth at Oahu,

distance = 40 miles = 40*5280'=211200'

The radius of the earth is

r=3960 miles=20908800'

and is perpendicular to the horizontal line above.

Hypotenuse

=sqrt(211200²+20908800²)

=2745600√(58)'

Visible height

= hypotenuse - radius of earth

= 1066.64' < 4961

Therefore the said peak is visible.

- Math -
**Jessica**, Saturday, November 17, 2012 at 6:53pmSo the question is basically asking which mountains peaks can be seen from Oahu.

Island Distance(Mi) Mountain Height(ft)

Lanai - 65 - Lanaihale - 3,370

Maui - 110 - Haleakala - 10,023

Hawaii - 190 - Mauna Kea - 13,796

Molokai - 40 - Kamakou - 4,961

A) Radius of earth= 3960 mi.

Determine angle formed at the center of the earth.

B) Determine length of the hypotenuse.

Is Lanai-hale visible from Oahu?

C) Repeat parts A & B for the other 3 islands

D) Which 3 Mountains are visible from Oahu?

Can someone draw me a diagram and explain to me what to do step by step? please and thank you!!

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