Saturday

July 23, 2016
Posted by **K** on Wednesday, May 25, 2011 at 10:46pm.

If 0.186 mol of HCONH2(g) dissciates in 2.16L at 400K, what will be the total pressure at equilibrium?

- Chemistry -
**DrBob222**, Wednesday, May 25, 2011 at 11:06pm............HCONH2 ==> NH3 + CO2

initial.....0.186 mols..0.....0

change.......-x.........x......x

equil.......0.186-x.....x......x

Substitute the above ICE chart into the Kc expression for the reaction and solve for x. That will give you moles NH3 and moles CO2. Add the moles together and substitute into PV = nRT to solve for pressure. - Chemistry -
**K**, Wednesday, May 25, 2011 at 11:39pmWhen I am solving for X my formula comes out to be

4.84 = X^2/ (.186-X)

Can I assume that x << .05 and eliminate it from the denominator and just solve for the equation 4.84 = X^2/.186? - Chemistry -
**DrBob222**, Wednesday, May 25, 2011 at 11:55pmNo, you may not make that assumption; however, I may have made an error. Let me think about this awhile. I'll post something different and erase what is there now or post a note that the original response stands.

- Chemistry -
**K**, Wednesday, May 25, 2011 at 11:57pmOkay thanks so much.

- Chemistry -
**DrBob222**, Thursday, May 26, 2011 at 12:03amOK. I made an error and the problem can't be solved that way. First, we convert moles to molarity.

(HCONH2) = 0.186/2.16L = 0.08611M

............HCONH2 ==> NH3 + CO2

initial.....0.08611M....0.....0

change.......-xM.........xM......xM

equil......0.08611-x M.....xM....xM

Substitute the above ICE chart into the Kc expression for the reaction and solve for x. That will give you M NH3, M CO2 and M HCONH2. Convert M to moles for each (M x L = moles), add the moles together and substitute into PV = nRT to solve for pressure. I will leave the original post there for the time being so you can make comparisons if you wish; however, I'll erase it before I go to bed tonight. I don't like to leave incorrect posts on the board. - Chemistry -
**K**, Thursday, May 26, 2011 at 12:08amOk thanks so much.

So when I solve for X I got

4.48(0.086 - x) = x^2

0.385 - 4.48x - x^2 = 0

Now i'd substitute that into the quadratic formula? Or is there an easier way to solve for X? - Chemistry -
**DrBob222**, Thursday, May 26, 2011 at 12:34amThat K is 4.84 and not 4.48 so you need to redo that part. When you solve that quadratic that gives you x (and I don't know of an easier way to do it.) Most calculators now have that built in to solve those things. I programmed mine to do that. That gives you x, use that to determine (HCONH2), (NH3), and (CO2), convert concns to moles, add the moles to find the total, then use PV = nRT to solve for P.

- Chemistry -
**K**, Thursday, May 26, 2011 at 12:38amOk this helps so much. Thanks a lot I appreciate it.