Homework Help: physics

Posted by cswidener on Wednesday, May 25, 2011 at 8:43pm.

A 870-kg race car can drive around an unbanked turn at a maximum speed of 41 m/s without slipping. The turn has a radius of 180 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 11000 N on the car. (a) What is the coefficient of static friction between the track and the car's tires? (b) What would be the maximum speed if no downforce acted on the car?

physics - Damon, Wednesday, May 25, 2011 at 8:49pm
down force = F = 870*9.81 + 11000

mu F = m v^2/R

mu (870*9.81 + 11000) = 870 (41)^2/180

for part b, same mu
mu(870*9.81) = 870 v^2/180
v^2 = 180*9.81*mu

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