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July 29, 2014

July 29, 2014

Posted by **oranges** on Wednesday, May 25, 2011 at 8:06pm.

- advance functions -
**Damon**, Wednesday, May 25, 2011 at 8:12pmlog2=log(x+5)-1

log 2 - log (x+5) = -1

log (2/(x+5)) = -1

10^log (2/(x+5)) = 10^-1 = 0.1

so

2/(x+5) = 0.1

2 = .1 x + .5

1.5 = .1 x

x = 15

- advance functions -
**oranges**, Wednesday, May 25, 2011 at 8:18pmoh right on! thanks!

- advance functions -
**Damon**, Wednesday, May 25, 2011 at 8:26pmYou are welcome :)

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