posted by Marisol on .
Given the plane 2x-3y+7z=4, find the equation for the line perpendicular to the plane that intersects the plane at the point (6,5,1).
vector 2i - 3j + 7 k is normal to the plane
(x-x1)/2 = (y-y1)/3 =(z-z1)/7
(x-6)/2 = (y-5)/3 = (z-1)/7