Math
posted by Marisol on .
Given the plane 2x3y+7z=4, find the equation for the line perpendicular to the plane that intersects the plane at the point (6,5,1).

vector 2i  3j + 7 k is normal to the plane
line
(xx1)/2 = (yy1)/3 =(zz1)/7
(x6)/2 = (y5)/3 = (z1)/7