Homework Help: Chemistry

Posted by SadFace on Wednesday, May 25, 2011 at 5:45pm.

When 0.5963g of a sample containing NaNO2 and some inert material is allowed to react with excess HSO3NH2, the volume of N2 gas produced is measured. The volume of N2 gas corrected to 298.15K and 100kPa is calculated to be 0.146L. Find the mass percent of NaNO2 in the sample using the molar volume of N2 at 298.15K and 100kPa (from the previous question). The molar volume from the previous question was 22.8 L/mol.

Chemistry - DrBob222, Wednesday, May 25, 2011 at 5:56pm
It would help greatly if you had an equation for the reaction.
Chemistry - Derek, Wednesday, May 25, 2011 at 5:59pm
NaNO2 + HSO3NH2 = NaHSO4 + H2O + N2
Chemistry - DrBob222, Wednesday, May 25, 2011 at 6:09pm
How many moles N2 do you have? That is 0.146L x (1 mol/22.8L) = ?? moles N2.
Using the coefficients in the balanced equation, convert moles N2 to moles NaNO2. (Hint: that is 1:1 ratio).
Convert moles NaNO2 to grams. grams = moles x molar mass.
%NaNO2 = (grams NaNO2/mass sample)*100 = ??
Chemistry - Sadface, Wednesday, May 25, 2011 at 6:11pm
YOU ROCKKK!!
Chemistry - DrBob222, Wednesday, May 25, 2011 at 6:27pm
I guess that's good?

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