Really hard Chemistry question that I need help with. Any assistance would be really helpful.?
When 0.5963g of a sample containing NaNO2 and some inert material is allowed to react with excess HSO3NH2, the volume of N2 gas produced is measured. The volume of N2 gas corrected to 298.15K and 100kPa is calculated to be 0.146L. Find the mass percent of NaNO2 in the sample using the molar volume of N2 at 298.15K and 100kPa (from the previous question). The molar volume from the previous question was 22.8 L/mol.
To find the mass percent of NaNO2 in the sample, we need to calculate the moles of N2 gas produced and then use that information to determine the moles of NaNO2 in the sample.
Step 1: Calculate the moles of N2 gas produced
Given:
- Volume of N2 gas corrected to 298.15K and 100kPa = 0.146L
- Molar volume of N2 at 298.15K and 100kPa (from the previous question) = 22.8 L/mol
We can use the ratio between the given volume and the molar volume to find the moles of N2 gas produced.
Moles of N2 gas = Volume of N2 gas (in L) / Molar Volume of N2 gas (in L/mol)
Moles of N2 gas = 0.146L / 22.8 L/mol
Step 2: Determine the moles of NaNO2 in the sample
Now, let's assume that x moles of NaNO2 are present in the sample.
The balanced chemical equation for the reaction between NaNO2 and HSO3NH2 is:
NaNO2 + HSO3NH2 → N2 + H2O
From the stoichiometry of the balanced equation, we can see that 1 mole of NaNO2 reacts to produce 1 mole of N2.
Therefore, the moles of NaNO2 in the sample are equal to the moles of N2 gas produced.
Step 3: Calculate the mass percent of NaNO2 in the sample
Given:
- Mass of the sample = 0.5963g
Mass percent of NaNO2 = (Mass of NaNO2 / Total mass of the sample) * 100
Mass percent of NaNO2 = (Moles of NaNO2 * Molar mass of NaNO2 / Mass of the sample) * 100
The molar mass of NaNO2 can be calculated using the atomic masses of sodium (Na), nitrogen (N), and oxygen (O).
Molar mass of NaNO2 = (1 * atomic mass of Na) + (1 * atomic mass of N) + (2 * atomic mass of O)
Step 4: Plug in the values and calculate the mass percent of NaNO2 in the sample
Substitute the values into the above equation and calculate the mass percent of NaNO2 in the sample.
I hope this helps you solve the problem! Let me know if you have any further questions.