Posted by **Pernell** on Wednesday, May 25, 2011 at 1:45pm.

Complete each of the following nuclear equations:

a. 239/92U - ? + o/-1e

b. 11/5B - 7/3Li + ?

thank you!

- Chemistry -
**DrBob222**, Wednesday, May 25, 2011 at 4:46pm
No arrow makes the equations difficult to read. I hope I interpreted the question correctly.

_{92}U^{239} ==> X + _{-1}e^{0}

The subscripts must add up on both sides and the superscripts must add up on both sides. On the left, we have 92 protons (+ charge) for U and on the right we have -1; therefore, X must be an element with 93 [because +93 +(-1) = +92)]. For the superscripts, we have 239 on the left and 0 on the right; therefore, the element X must have a mass number of 239 (239+0=239). What is element X? Look on the periodic chart for element number 93. That is Np. Therefore, we write that as

_{93}Np^{239}

I know the mass number is supposed to go in the upper left corner but since it is difficult to write both a subscript and a superscript in the same spot with a computer, I placed the atomic number as a subscript in the correct place and used the upper right corner for the mass number since we don't need to worry about the charge on the U or Np.

## Answer This Question

## Related Questions

- chem - Supply the missing atomic symbol to complete the equation for the ...
- Chemistry - Write a nuclear equation for the following: Iodine 131 undergoes ...
- chemistry - fill in the missing symnbols in the following nuclear bombardment ...
- chemistry - Balance these nuclear equations. Can some please help I dont ...
- Chemistry - Plutonium-239 is used in nuclear bombs. Determine the number of ...
- CHEM - Pu-239 has a half-life of 24110 y. If 1.00 kg of this isotope is present ...
- Chemistry - Can somebody help me calculate the energy released when 1g of ...
- CHEMISTRY - Suppose you had a detection device that could count every decay ...
- Chemistry - How would I solve this: The atomic mass of 6/3Li and 7/3Li are 6....
- calculus - Question: "Plutonium isotope Pu-239 has a half-life of 24,100 years. ...

More Related Questions