Posted by **Loren** on Wednesday, May 25, 2011 at 12:42pm.

Let R = {0,1,2,3}be the range of h(x)= x-7. The domain of h is?

- algebra -
**MathMate**, Thursday, May 26, 2011 at 10:00am
h(x)=x-7

h^{-1}(x)=x+7

From

range of h(x) = domain of h^{-1}(x)

and

domain of h(x) = range of h^{-1}(x)

We conclude that the domain of h(x) is the same as the range of

h^{-1}(x)=x+7

where the domain of h^{-1}(x) is {0,1,2,3}.

For example:

h^{-1}(0)=0+7=7

...

domain of h(x) is therefore {7,...}

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