Posted by Loren on Wednesday, May 25, 2011 at 12:42pm.
h(x)=x-7
h-1(x)=x+7
From
range of h(x) = domain of h-1(x)
and
domain of h(x) = range of h-1(x)
We conclude that the domain of h(x) is the same as the range of
h-1(x)=x+7
where the domain of h-1(x) is {0,1,2,3}.
For example:
h-1(0)=0+7=7
...
domain of h(x) is therefore {7,...}
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