algebra
posted by Loren on .
Let R = {0,1,2,3}be the range of h(x)= x7. The domain of h is?

h(x)=x7
h^{1}(x)=x+7
From
range of h(x) = domain of h^{1}(x)
and
domain of h(x) = range of h^{1}(x)
We conclude that the domain of h(x) is the same as the range of
h^{1}(x)=x+7
where the domain of h^{1}(x) is {0,1,2,3}.
For example:
h^{1}(0)=0+7=7
...
domain of h(x) is therefore {7,...}