Posted by **pavatharani** on Wednesday, May 25, 2011 at 11:38am.

a stone is thrown vertically upward with an initial velocity v0. the distance travelled by it in time 1.5v0/g?

- physica -
**Jai**, Wednesday, May 25, 2011 at 11:51am
recall that the motion of the stone is uniformly accelerated motion (because it accelerated due to gravity). thus we can use the formula:

h = vo*t - 1/2(g)(t^2)

where

h = height

vo = initial velocity

t = time

g = acceleration due to gravity = 9.8 m/s^2

substituting,

h = vo*(1.5*vo/g) - (1/2)(g)(1.5*vo/g)^2

h = 1.5*[(vo)^2]/g - 1.125*[(vo)^2]/g

h = 0.375*[(vo)^2]/g

hope this helps~ :)

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