Posted by ale on Wednesday, May 25, 2011 at 11:24am.
A 2000 pound car is parked on a street that makes an angle of 12* with the horizontal (think it's a street on a hill). a) find the magnitude of the force required to keep the car from rolling down the hill. b) Find the force perpendicular to the street.

trig  Henry, Thursday, May 26, 2011 at 7:59pm
mass = 2000lbs * 0.454kg/lb = 908kg.
Fc = mg = 908kg * 9.8N/kg = 8898.4N @
12deg.
a. Fp = 8898.4*sin(12) = 1850.4N. = Force parallel to the street = Force required to keep the car from roling down hill.
b. Fv = 8898.4 * cos12 = 8704N = Force
perpendicular to the street.

PreCal: Vectors  Marie, Monday, April 18, 2016 at 2:44pm
a. Force to prevent car from rolling = v
v=<cos12°,sin12°>
F=projvF=(F•v/v^2)v= (F•v)v
<0,2000>•<cos12,sin12>= 0+2000sin12 = 415.82lbs
b. Find the angle of the perpendicular in relation to the force of 2000lbs. To do this, I drew a triangle, one line horizontal, one line being the 12° angle between it and the horizontal, and one being perpendicular to the 12° line(90°). Connect the lines and the third angle should be 78°.
Then you do the same as the last.
Force to prevent car from rolling(perpendicular) = c
c=<cos78°,sin78°>
F=projcF=(F•v/v^2)v= (F•v)v
<0,2000>•<cos78,sin78>= 0+2000sin78 = 1956.3lbs

Yo MUM  Anonymous, Tuesday, July 12, 2016 at 3:39pm
Ask ur mom
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