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October 31, 2014

October 31, 2014

Posted by **ale** on Wednesday, May 25, 2011 at 10:58am.

- trig -
**drwls**, Wednesday, May 25, 2011 at 11:52amThe way you have worded the problem, with the word "bearing",

460 mph at bearing 460 mph is the actual ground speed and direction of the airplane.

I suspect that they meant 460 mph at 170 to be the air speed and heading of the place, and that they want you to solve for the ground speed and direction by adding the wind velocity vector.

In that case:

ground speed components are:

Vy (north component) = 460 cos 170 + 80 cos 200 = -528.19 mph

Vx(east component) = 460 sin170 + 80 sin200 = 52.52 mph

Ground speed = 530.79 mph

bearing = arctan Vx/Vy = 174.2 degrees

- trig -
**Shreena**, Wednesday, March 6, 2013 at 7:54pmAn airplane flying at 550 mph has a bearing of N 58 E. After flying for 1.5 hours, how far north and how far east has the plane traveled from its point of departure?

- trig -
**gremlin**, Sunday, May 5, 2013 at 12:55pmharghargharg

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