Posted by alan on Wednesday, May 25, 2011 at 10:20am.
This expression has been the subject of a recent differential equation problem.
dy/dx=(2/27)(x-3)√((x^2-6x+23)/y)
in which case we can rearrange as
(√y)dy/dx=(2/27)(x-3)√(x^2-6x+23)
The given expression above is not an equation, so we do not know exactly what the expression equals (dy/dx, 0, 1...?)
Related Questions
math - dy/dx=2/27(x-3)√((x^2-6x+23)/y)
rearrange this equation - Rearrange to make f the subject, showing your work ...
calculus - I posted this below, and no one answered. Please help with this very ...
calculus - I posted this below, and no one answered. Please help with this very ...
Calculus - Using 3(x-3)(x^2-6x+23)^1/2, as the chain rule differentiation of f(x...
algebra 1 - alright i have a few questions if its ok..? Simplify: 1. -2&#...
Math - Hello.I need to rearrange the following to make b the subject' a = 10...
calculus - Sorry to post this again, but I am still unable to understand it and ...
maths - (a)(i)use the composite rule to differentiate the function f(x)=(x^2-6x+...
calculus - Please help with this very complicated question! Using 3(x-3)(x^2-6x+...
For Further Reading
