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maths....(mathematics..)

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by prime factorisation method find the least positive number divisible by 700 and 364

  • maths....(mathematics..) -

    First you have to prime factorize both numbers. The greatest common divisor(GCD) has the
    lower number of prime factors that appear in both lists.

    2 appears twice and 7 appears once on both lists 5,7 and 13 appear on one list only, so they and not "common" factors and do not appear in the GCD

    364 = 91*4 = 2^2 * 7 * 13
    700 = 2^2 * 5^2 * 7

    GCD = 2^2 * 7 = 28

  • maths....(mathematics..) -

    700 = 7x2x2x5x5
    364 = 2x2x91

    HCM = 7x2x2x5x5x91 = 63700

  • correction - maths....(mathematics..) -

    I assumed 91 was prime, ...

    700 = 7x2x2x5x5
    364 = 2x2x7x13

    LCM = 7x2x2x2x2x13 = 9100

  • maths....(mathematics..) -

    I read the problem incorrectly

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