Posted by **....** on Wednesday, May 25, 2011 at 8:20am.

by prime factorisation method find the least positive number divisible by 700 and 364

- maths....(mathematics..) -
**drwls**, Wednesday, May 25, 2011 at 8:30am
First you have to prime factorize both numbers. The greatest common divisor(GCD) has the

lower number of prime factors that appear in both lists.

2 appears twice and 7 appears once on both lists 5,7 and 13 appear on one list only, so they and not "common" factors and do not appear in the GCD

364 = 91*4 = 2^2 * 7 * 13

700 = 2^2 * 5^2 * 7

GCD = 2^2 * 7 = 28

- maths....(mathematics..) -
**Reiny**, Wednesday, May 25, 2011 at 8:33am
700 = 7x2x2x5x5

364 = 2x2x91

HCM = 7x2x2x5x5x91 = 63700

- correction - maths....(mathematics..) -
**Reiny**, Wednesday, May 25, 2011 at 8:36am
I assumed 91 was prime, ...

700 = 7x2x2x5x5

364 = 2x2x7x13

LCM = 7x2x2x2x2x13 = 9100

- maths....(mathematics..) -
**drwls**, Wednesday, May 25, 2011 at 10:22am
I read the problem incorrectly

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