Math
posted by Haven on .
A choir is performing for the school fall festival. On the first night 12 choir members were missing so they stood in 5 equal rows. On the sencond night, 1 member was missing so they stood in 6 even rows. How many choir members are there?

Let N=number of choir members.
Then for the first night,
N=5m+12
for the second night,
N=6n+1
We look for the smallest number which when divided by 5 gives a remainder of 2, and when divided by 6 gives a remainder of 1.
Possible values:
N=17,22,27,32,37,42,47,52,57,62,67,72,...
N=7,13,19,25,31,37,43,49,55,61,67,72
So the minimum number of choir members is 37. Other possibilities are 67,97,127,...