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October 20, 2014

October 20, 2014

Posted by **Julie** on Tuesday, May 24, 2011 at 4:58pm.

- Algebra -
**MathMate**, Tuesday, May 24, 2011 at 5:38pmw^4-6w^2-2=0

(w²)^2;-6(w²)-2 = 0

put x=w²

x^2-6x-2=0

Apply the quadratic formula:

x=(6±√(36+8))/2

=3±√(11)

Therefore

w=±√(3±√(11))

(for a total of 4 solutions)

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