-7 and -4 the quadratic equation is?
Thank you in advance :)
This makes no sense.
do you mean
(x+7)(x+4)=0 where the roots are -4,-7?
FOIL it out.
x=-7 and x=-4
x+7=0 and x+4=0
(x+7)(x+4) = x^2 + 4x + 7x +28
the equation would be x^2 + 11x + 28
correct
To find the quadratic equation given two roots, (-7 and -4 in this case), we can use the fact that the sum of the roots is equal to the negation of the coefficient of the linear term (x-term), and the product of the roots is equal to the constant term (c-term) divided by the coefficient of the quadratic term (x^2 term).
Let's assume the quadratic equation is of the form: ax^2 + bx + c = 0.
1. Find the sum of the roots:
The sum of the roots is given by: -b/a = -((-7) + (-4)) = 11/a.
2. Find the product of the roots:
The product of the roots is given by: c/a = ((-7) * (-4))/a = 28/a.
From step 1, we have: 11/a = -b/a.
Cross-multiplying, we get: 11 = -b.
From step 2, we have: 28/a = c/a.
Cross-multiplying, we get: 28 = c.
So, the quadratic equation with roots -7 and -4 is: x^2 - 11x + 28 = 0.