March 30, 2017

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a rocket is launched from atop a 105-foot cliff with an initial velocity of 156 ft/s.The height of the rocket above the ground at time or t is given by h=-16tsquared+156t+105. When will the rocket hit the ground after it is launched?

  • physics - ,

    when is h= 0?

    0=h(t)=-16t^2 + 156t+105

    solve for t.

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