Posted by **Dick** on Tuesday, May 24, 2011 at 8:34am.

n order to study the amounts owed to the city council, a city clerk takes a random sample of 16 files from a cabinet containing a large number of delinquent accounts and finds the average amount owed to the city to be $231. It has been claimed that the true mean amount owed on accounts of this type is greater than $250. If it is appropriate to assume that the amount owed is a normally distributed random variable with a standard deviation of $40, then the value of the test statistic appropriate for testing the claim is

- Statistics -
**PsyDAG**, Tuesday, May 24, 2011 at 10:53am
Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)(You can use n for simplicity.)

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to that Z score.

- Statistics -
**bill**, Friday, May 25, 2012 at 5:26am
0.246?

## Answer This Question

## Related Questions

- Statics - A power company takes a random sample of its delinquent account files...
- Statistics - A survey organization takes a simple random sample of 625 ...
- statistics - According to a survey, 21% of motorists in a large city are ...
- Statistics - City A has 1,000,000 people; City B has 4,000,000 people. Suppose ...
- Statistics - A random sample of 384 people in a mid-sized city (city one) ...
- Statistics - A random sample of 384 people in a mid-sized city (city one) ...
- college stats - help please!!! 1. The average number of bumped passengers per ...
- statistics - Suppose you are trying to estimate the percent of women in a city. ...
- statistics - Suppose you are trying to estimate the percent of women in a city. ...
- Statistics and Probability - I took a large sample of households in a city, and ...

More Related Questions