Posted by **Joe** on Monday, May 23, 2011 at 10:36pm.

A box containing Munchkins contains chocolate and glazed donut holes. If Gloria ate 2 chocolate Munchkins, then 1/11 of the remaining Munchkins would be chocolate. If Gloria added 4 glazed Munchkins to the box, 1/7 of the Munchkins would be chocolate. How many Munchkins are in the original box?

- math - typo in question -
**MathMate**, Tuesday, May 24, 2011 at 7:50am
If Gloria added 4 glazed Munchkins to the box, the proportion of chocolate *increased* from 1/11 to 1/7?

You will get negative numbers as answers.

Below, I assume you have switched the two proportions between 1/11 and 1/7.

If my guess proves to be wrong, the solution method remains the same.

G = glazed

C = chocolate

7(C-2) = G + C-2

11(C-2) = G+4 + C-2

or

6C-G =12

10C-G = 24

Solve for G and C to get

G=6, C=3

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