Posted by **Joe** on Monday, May 23, 2011 at 10:36pm.

A box containing Munchkins contains chocolate and glazed donut holes. If Gloria ate 2 chocolate Munchkins, then 1/11 of the remaining Munchkins would be chocolate. If Gloria added 4 glazed Munchkins to the box, 1/7 of the Munchkins would be chocolate. How many Munchkins are in the original box?

- math - typo in question -
**MathMate**, Tuesday, May 24, 2011 at 7:50am
If Gloria added 4 glazed Munchkins to the box, the proportion of chocolate *increased* from 1/11 to 1/7?

You will get negative numbers as answers.

Below, I assume you have switched the two proportions between 1/11 and 1/7.

If my guess proves to be wrong, the solution method remains the same.

G = glazed

C = chocolate

7(C-2) = G + C-2

11(C-2) = G+4 + C-2

or

6C-G =12

10C-G = 24

Solve for G and C to get

G=6, C=3

## Answer This Question

## Related Questions

- Math - A box containing Munchkins contains chocolate and glazed donut holes. If ...
- math - a box of munchkins contains chocolate and glazed donut holes. if Gloria ...
- Math/Probability - For example, you have to pick a donut from a box randomly ...
- Math - 1. A chocolate bar is made up of 12 equal pieces.Tom ate 3/4 of a ...
- Maths - In a box of chocolates, •one-fifth are plain chocolate •one-sixth are ...
- math - Amy, Beth , Gretchen and Deb each had a 2 large chocolate bars. Each ...
- > Finite Math - Colleen observed a candy store and counted the number of ...
- Maths - Theo had two-thirds of a box of chocolates left. He and his two sisters...
- Math - Erika eat 1/3 of a chocolate bar and gave the remaining 2/3 of the ...
- health - yesterday, when i ate chocolate cereal dry, it taste good, but when I ...

More Related Questions