A box containing Munchkins contains chocolate and glazed donut holes. If Gloria ate 2 chocolate Munchkins, then 1/11 of the remaining Munchkins would be chocolate. If Gloria added 4 glazed Munchkins to the box, 1/7 of the Munchkins would be chocolate. How many Munchkins are in the original box?
math - typo in question - MathMate, Tuesday, May 24, 2011 at 7:50am
If Gloria added 4 glazed Munchkins to the box, the proportion of chocolate increased from 1/11 to 1/7?
You will get negative numbers as answers.
Below, I assume you have switched the two proportions between 1/11 and 1/7.
If my guess proves to be wrong, the solution method remains the same.
G = glazed
C = chocolate
7(C-2) = G + C-2
11(C-2) = G+4 + C-2
10C-G = 24
Solve for G and C to get