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October 1, 2014

October 1, 2014

Posted by **Anonymous** on Monday, May 23, 2011 at 8:43pm.

- Finite Math -
**Reiny**, Monday, May 23, 2011 at 9:08pmTo get 40% or more, you cannot have

0, 1, 2, or 3 only correct answers

prob(0 right) = C(10,0) (1/5)^0 (4/5)^10 = .10737

prob(1 right) = C(10,1)(1/5)(4/5)^9 = .26844

prob(2right) = C(10,2)(1/5)^2(4/5)^8 = .30199

prob(3right) = C(10,3)(1/5)3 (4/5)^7 = . 20133

total = .87913

so prob of passing by just guessing = 1 - .87913 = .1209

check my arithmetic, the procedure is correct.

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