Posted by Ashley on .
A triangle has side lengths of (x+4), (4x8), and (2x+8) units. If the perimeter of the triangle is at least 88 units, what is the minimum length of each side of the triangle?

Prealgebra (DESPRATE NEED OF HELP!) 
MathMate,
The length of each side can be calculated by the distance formula.
For example, between (x+4) and (4x8), the distance is:
sqrt((4xx)^2+(84)^2)
Sum the three sides and force the inequality of
∑lengths≥88.
Solve for x.
Note that the sides of the triangle are monotonically increasing, which means that the sum is also.
You can solve by an iterative process. I get x(min)=13.55...
So the lengths of each side can be calculated accordingly. 
Prealgebra (DESPRATE NEED OF HELP!) 
Reiny,
x+4 + 4x8 + 2x+8 ≥ 88
7x + 4 ≥ 88
7x ≥ 84
x ≥ 12
plug x = 12 into each of the side expressions 
Prealgebra !! 
MathMate,
Thanks Reiny, I wasn't reading the question right!
Sorry, Ashley, please go with Reiny's answer.