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February 1, 2015

February 1, 2015

Posted by **Jet** on Monday, May 23, 2011 at 7:52pm.

ab^2, a^2b^5, a^3B^8, ...; t25

really stumped.

I know that r= (a^2b^5)/ab^2 but I don't know what to do next.

ab^2 ((a^2b^5)/ab^2)^n-1 ??

- Algebra 2 -
**MathMate**, Tuesday, May 24, 2011 at 10:45amr= (a^2b^5)/ab^2 = ab³

therefore

t(n)=a^n b^(3n-1)

Check:

t(1)=a^1b^(3-1)=ab²

t(2)=a^2b^(2*3-1)=a²b^5

t(3)=a^3b^(3*3-1)=a³b^8

...

So

t(25)=?

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