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posted by corey on Monday, May 23, 2011 at 7:37pm.

There are 6 boys and 8 girls in a group of students. Calculate the number of ways that a committee of 3 students which has at least 1 girl can be selected from the group. Please show your work.

Number of ways to choose 3 students from 14 = C(14,3) = 14!/((14-3)!3!) Number of ways to choose 3 students from 8 boys = C(8,3) = 8!/((8-3)!3!) Number of ways to choose 3 students with at least one girl = C(14,3)-C(8,3)

thank you!

You're welcome!

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