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April 1, 2015

April 1, 2015

Posted by **miles** on Monday, May 23, 2011 at 1:20pm.

- calculus iii -
**Reiny**, Monday, May 23, 2011 at 2:01pmThe information translated into triangle ABC,

where BC is vertical and magnitude 837

AB is our required vector

and angle C = 168.5°

by cosine law

|AB|^2 = 837^2 + 63^2 - 2(837)(63)cos 168.5°

|AB| = 898.82

by sine law:

Sin B / 63 = sin168.5/898.82

sinB = .013974

B = .8 °

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