Post a New Question

Chemistry

posted by .

If 15.omL of 0.0250 M aqueous H2SO4 is required to neutralize 10.0 mL of aqueous solution of KOH, what is the molarity of the KOH solution?

  • Chemistry -

    2KOH + H2SO4 ==> K2SO4 + 2H2O
    moles H2SO4 = M x L = ??
    Convert moles H2SO4 to moles KOH. It will be ??mole H2SO4 x 2 = moles KOH.
    M KOH = moles KOH/L KOH

  • Chemistry -

    BMAVA=AMBVB 2(0. 25)(15)=1(10)(MB) 0.75/10=10MB/10 MB=0.075M ANSWERED

  • Chemistry -

    .25

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question