Posted by meeeeee on Sunday, May 22, 2011 at 10:37pm.
find the volume of the cup. the diameter of the top is 3inches. the diameter of the base is 2inches. the height is 4inches.

math  MathMate, Monday, May 23, 2011 at 9:59am
If you draw a picture, and imagine that the truncated cone is produced to its vertex V where the diameter is zero, then
height from V to the section at which the diameter is 2"
= 2*4" = 8"
Height of complete cone = 4"+8"=12"
Height of "missing" cone = 8"
Volume of complete cone
= πr²h/3
= 12π(3/2)²/3
= 9π
Volume of "missing" cone
=πr²h/3
=8π(2/2)²/3
=(8/3)π
Therefore volume of the truncated cone
= 9π  (8/3)π
= ...
Volume of comp
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