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November 1, 2014

November 1, 2014

Posted by **meeeeee** on Sunday, May 22, 2011 at 10:37pm.

- math -
**MathMate**, Monday, May 23, 2011 at 9:59amIf you draw a picture, and imagine that the truncated cone is produced to its vertex V where the diameter is zero, then

height from V to the section at which the diameter is 2"

= 2*4" = 8"

Height of complete cone = 4"+8"=12"

Height of "missing" cone = 8"

Volume of complete cone

= πr²h/3

= 12π(3/2)²/3

= 9π

Volume of "missing" cone

=πr²h/3

=8π(2/2)²/3

=(8/3)π

Therefore volume of the truncated cone

= 9π - (8/3)π

= ...

Volume of comp

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